Pembahasan TPA Deret SNMPTN 2011 (Kode Soal 773)

1. 3, 5, 9, 17, …

A. 29

B. 31

C. 33

D. 35

E. 37

Pembahasan :

$u_1 = 3$

$u_2 = u_1 + 2 = 5$

$u_3 = u_2 + 4 = 9$

$u_4 = u_3 + 8 = 17$

$u_5 = u_4 + 16 = 33$

Jawaban : C

2. 3, 17, 35, 65, 99, 145, …

A. 168

B. 170

C. 195

D. 196

E. 197

Pembahasan :

3		17		35		65		99		145		195
	14		18		30		34		46		50
		4		12		4		12		4

Jawaban : C

3. 11, 14, 19, 26, 35, 38, 43, 50, …

A. 53

B. 55

C. 57

D. 58

E. 59

Pembahasan :

$u_1 = 11$

$u_2 = u_1 + 3 = 14$

$u_3 = u_2 + 5 = 19$

$u_4 = u_3 + 7 = 26$

$u_5 = u_4 + 9 = 35$

$u_6 = u_5 + 3 = 38$

$u_7 = u_6 + 5 = 43$

$u_8 = u_7 + 7 = 50$

$u_9 = u_8 + 9 = 59$

Jawaban : E

4. 4, 4, 4, 7, 5, 4, 5, 8, 6, 4, …, …

A. 5, 9

B. 6, 9

C. 6, 8

D. 6, 6

E. 6, 5

Pembahasan :

$u_1 = 4$

$u_3 = u_1 = 4$

$u_5 = u_3 + 1 = 5$

$u_7 = u_5 = 5$

$u_9 = u_1 + 1 = 6$

$u_{11} = u_9 = 6$

$u_2 = 4$

$u_4 = u_2 + 3 = 7$

$u_6 = u_2 = 4$

$u_8 = u_6 + 4 = 8$

$u_{10} = 4$

$u_{12} = u_{10} + 5 = 9$

Jawaban : B

5. 1, 1, 2, 4, 7, 13, 25, …

A. 31

B. 38

C. 49

D. 50

E. 55

Pembahasan :

1		1		2		4		7		13		25		49
	0		1		2		3		6		12		24
		+1		+1		+1		x2		x2		x2

Jawaban : C

6. 11, 12, 13, 10, 13, 14, 15, 16, …, …

A. 13, 16

B. 13, 17

C. 14, 17

D. 17, 14

E. 19, 20

Pembahasan :

$u_1 = 11$

$u_2 = u_1+1 = 12$

$u_3 = u_3+1 = 13$

$u_4 = u_3-3 = 10$

$u_5 = u_4 + 3 = 13$

$u_6 = u_5+1 = 14$

$u_7 = u_6+1 = 15$

$u_8 = u_7+1 = 16$

$u_9 = u_8-3 = 13$

$u_{10} = u_9+3 = 16$

Jawaban : A

7. 1, 5, 4, 3, 7, 1, 10, -1, 13, -3, …, …

A. 16, -8

B. 10, -5

C. 15, 8

D. 16, -5

E. 4, 27

Pembahasan :

$u_1 = 1$

$u_3 = u_1 + 3 = 4$

$u_5 = u_3 + 3 = 7$

$u_7 = u_5 + 3 = 10$

$u_9 = u_7 + 3 = 13$

$u_{11} = u_9 + 3 = 16$

$u_2 = 5$

$u_4 = u_2-2 = 3$

$u_6 = u_4-2 = 1$

$u_8 = u_6-2 = -1$

$u_{10} = u_8-2 = -3$

$u_{12} = u_{10}-2 = -5$

Jawaban : D

8. 2, 5, 4, 6, 6, 7, 8, 8, …

A. 7

B. 8

C. 9

D. 10

E. 12

Pembahasan :

$u_1 = 2$

$u_3 = u_1 + 2 = 4$

$u_5 = u_3 + 2 = 6$

$u_7 = u_5 + 2 = 8$

$u_9 = u_7 + 2 = 10$

Jawaban : D

9. $\dfrac{1}{2}, \dfrac{2}{8}, \dfrac{3}{26}, \dfrac{4}{80}, \ldots$

A. $\dfrac{5}{241}$

B. $\dfrac{5}{242}$

C. $\dfrac{5}{243}$

D. $\dfrac{5}{244}$

E. $\dfrac{5}{245}$

Pembahasan :

Perhatikan penyebut pecahan tersebut

2		8		26		80		242
	6		18		54		162
		x3		x3		x3

Jawaban : D

10.212, 101, 313, -212, 101, -313, -212, -101, …, …

A. -313, 212

B. -313, -212

C. 313, -212

D. 212, 101

E. -212, -101

Pembahasan :

$u_1 = 212$

$u_2 = u_1-101 = 101$

$u_3 = u_1 + u_2 = 313$

$u_4 = u_2-u_3 = -212$

$u_5 = u_3 + u_4 = 101$

$u_6 = u_4-u_5 = -313$

$u_7 = u_5 + u_6 = -212$

$u_8 = u_6-u_7 = -101$

$u_9 = u_7 + u_8 = -313$

$u_{10} = u_8-u_9 = 212$

Jawaban : A

NOTE : silahkan dikoreksi dan berikan komentar jika ada kesalahan atau masih ada keambiguan dalam penyelesaian soal-soal ini.

Tinggalkan Balasan Batalkan balasan

Ketikkan komentar di sini...

Isikan data di bawah atau klik salah satu ikon untuk log in:

Surel (wajib) (Alamat takkan pernah dipublikasikan)

Nama (wajib)

Situs Web

You are commenting using your WordPress.com account. ( Logout / Ubah )

You are commenting using your Twitter account. ( Logout / Ubah )

You are commenting using your Facebook account. ( Logout / Ubah )

You are commenting using your Google+ account. ( Logout / Ubah )

Batal

Connecting to %s

	vita di Metode Bagi-Dua (Bisection…
	ngurah di Koleksi Buku
	Indah Fadillah di Kumpulan Soal Test Matematika…
	ira vanny sinaga di Tanya Jawab MATEMATIKA
	nauval di Tanya Jawab MATEMATIKA
	Z di Penyelesaian Persamaan Linier…
	ahmad kurnia di Menghitung Determinan Mengguna…
	Isna di Tanya Jawab MATEMATIKA
	Jeki di Tanya Jawab MATEMATIKA
	Jeki di Tanya Jawab MATEMATIKA

Share this:

Sukai ini:

Terkait

Tinggalkan Balasan Batalkan balasan